Relations and Functions MCQ Questions for Class 11 Maths Chapter 2 with Answers

(i) [– 1, 1]
(ii) (– 1, 1)
(iii) (– 3, 3)
(iv) (– 3, 1)

(i) [– 1, 1]

Q2. If the function f : R → R be given by f(x) = x² + 2 and g : R → R is given by g(x) = x/(x – 1). The value of gof(x) is

(i) (x² + 2)/(x² + 1)
(ii) x²/(x² + 1)
(iii) x²/(x² + 2)
(iv) none of these

(i) (x² + 2)/(x² + 1)

Q3. If f is an even function and g is an odd function the fog is a/an

(i) Even function
(ii) Odd function
(iii) Either even or odd function
(iv) Neither even nor odd function

(i) Even function

Q4. Two functions f and g are said to be equal if f

(i) the domain of f = the domain of g
(ii) the co-domain of f = the co-domain of g
(iii) f(x) = g(x) for all x
(iv) all of above

(iv) all of above

(i) (1/3, 1)
(ii) [1/3, 1)
(iii) (1/3, 1]
(iv) R

(iv) R

Q6. If A is the null set and B is an infinite set, then what is A×B ?

(i) Infinite set
(ii) f
(iii) Undefined
(iv) A singleton set

(iii) Undefined

(i) 29
(ii) 92
(iii) 32
(iv) 29 – 1

(i) 29

Q8. Let A={1,2,3,4,5} and R be a relation from A to A, R = {(x, y): y = x + 1}. Find the domain.

(i) {1,2,3,4,5}
(ii) {2,3,4,5}
(iii) {1,2,3,4}
(iv) {1,2,3,4,5,6}

(i) {1,2,3,4,5}

(i) 2
(ii) 4
(iii) 8
(iv) 16

(iv) 16

(i) 2, 1
(ii) -2, 1
(iii) 2, -1
(iv) -2, -1

(iii) 2, -1

Q11. A relation R is defined from the set of integers to the set of real numbers as (x, y) = R if x² + y² = 16 then the domain of R is

(i) (0, 4, 4)
(ii) (0, -4, 4)
(iii) (0, -4, -4)
(iv) None of these

(ii) (0, -4, 4)

Q12. A function f(x) is said to be an odd function if

(i) f(-x) = f(x)
(ii) f(-x) = -f(x)
(iii) f(-x) = k * f(x) where k is a constant
(iv) None of these

(ii) f(-x) = -f(x)

(i) 3
(ii) 5
(iii) 7
(iv) 9

(iv) 9

Q14. If A = {1, 2, 3}, B = {1, 2} and C = {2, 3}, which one of the following is correct ?

(i) (A´B)Ç(B´A) = (A´C)Ç(B´C)
(ii) (A´B)Ç(B´A) = (C´A)Ç(C´B)
(iii) (A´B)È(B´A) = (A´B)È(B´C)
(iv) (A´B)È(B´A) = (A´B)È(A´C)

(iii) (A´B)È(B´A) = (A´B)È(B´C)

Q15. Let R be the set of real numbers. If f(x) = x² and g(x) = 2x + 1, then fog(x) is equal to

(i) 2x + 1
(ii) 2x² + 1
(iii) (2x + 1)²
(iv) None of these

(ii) 2x² + 1

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